Some tips for verifying identities are the following:
- Try to express everything in sin's and cos's.
- Only work with one side of the equation.
Here is an example of a verifying problem; I will list out the steps as I solve it:
cos(–θ) / [1+sin(–θ)] = secθ + tanθ
Use the Even and Odd identities to simplify the terms containing –θ:
cosθ / (1 – sinθ) =
Multiply the numerator and denominator with the conjugate of the denominator:
[cosθ × (1 + sinθ)] / [(1 – sinθ) × (1 + sinθ)] =
Distribute:
(cosθ + cosθsinθ) / (1 – sin2θ) =
Use the Pythagorean identity sin2θ + cos2θ = 1 to change the denominator to cos2θ:
(cosθ + cosθsinθ) / cos2θ =
Split this fraction into two fractions:
(cosθ / cos2θ) + (cosθsinθ / cos2θ) =
Cancel out the cos's:
(1 / cosθ) + (sinθ / cosθ) =
Use the Reciprocal identity 1 / cosθ = secθ and the Quotient identity sinθ / cosθ = tanθ to rewrite the fractions:
secθ + tanθ = secθ + tanθ
Since the LHS (left-hand side) is now equal to the RHS (right-hand side), the verification is done!
Use the Even and Odd identities to simplify the terms containing –θ:
cosθ / (1 – sinθ) =
Multiply the numerator and denominator with the conjugate of the denominator:
[cosθ × (1 + sinθ)] / [(1 – sinθ) × (1 + sinθ)] =
Distribute:
(cosθ + cosθsinθ) / (1 – sin2θ) =
Use the Pythagorean identity sin2θ + cos2θ = 1 to change the denominator to cos2θ:
(cosθ + cosθsinθ) / cos2θ =
Split this fraction into two fractions:
(cosθ / cos2θ) + (cosθsinθ / cos2θ) =
Cancel out the cos's:
(1 / cosθ) + (sinθ / cosθ) =
Use the Reciprocal identity 1 / cosθ = secθ and the Quotient identity sinθ / cosθ = tanθ to rewrite the fractions:
secθ + tanθ = secθ + tanθ
Since the LHS (left-hand side) is now equal to the RHS (right-hand side), the verification is done!
Great blog post! I liked how you started off with 2 basic tips for verifying trig identities and then you progressed to a worked-out example. The identities used for each step were also clearly labeled and explained.
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